Coulomb's law and point charges Cambridge International AS & A Level Physics revision
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In plain words
Two charges push or pull on each other with a force that follows the same pattern as gravity: it depends on both charges, and falls off with the square of the distance. The big differences are that it can repel as well as attract, and that it is enormously stronger.
5 things to know
- Coulomb's law: F = Q₁Q₂ ÷ 4πε₀r², where ε₀ = 8.85 × 10⁻¹² F/m. The constant 1 ÷ 4πε₀ is 8.99 × 10⁹ N m² C⁻². Like charges repel and unlike charges attract.
- For any point outside a charged conducting sphere, the charge behaves as if it were all at the centre.
- The field strength at a distance r from a point charge Q is E = Q ÷ 4πε₀r².
- Both are inverse square laws: at twice the distance, the force and the field strength are a quarter as big.
- Field strength is a vector. To find the field due to several charges, add their fields with direction taken into account.
Worked example
Find the force between charges of +2.0 µC and +3.0 µC that are 0.10 m apart.
- F = Q₁Q₂ ÷ 4πε₀r² = 8.99 × 10⁹ × 2.0 × 10⁻⁶ × 3.0 × 10⁻⁶ ÷ 0.10².
- = 0.0539 ÷ 0.010.
- = 5.4 N, and it is a repulsion, because both charges are positive.
Tips and tricks
- Change µC and nC to coulombs and centimetres to metres, and remember to square r.
- Work out the size of the force from the sizes of the charges, then decide the direction from their signs.
It lands in your notebook with its questions as flashcards.
Coulomb's law and point charges: 5 questions and answers
These are the quiz’s questions. Do the quiz first, then come back here for the ones that got you.
The distance between two charges is doubled. What happens to the force between them?
The force is proportional to 1 ÷ r².
What do two negative charges do to each other?
Like charges repel.
Both of two charges are doubled, and the distance stays the same. What happens to the force between them?
The force is proportional to the product of the charges.
How does the field strength at a distance 2r from a point charge compare with the field strength at r?
E is proportional to 1 ÷ r².
For points outside a charged conducting sphere, where does its charge seem to be?
The same idea as treating a planet's mass as being at its centre.
Quiz
5 questions
Tap an answer and you’ll see straight away whether it’s right, and why.
Worksheet
4 questions, 9 marks. Write your answers on paper, then check them.
Coulomb's law and point charges
Cambridge International AS & A Level Physics 9702 · 9 marks · papermunch.org
Name ______________________________ Date ______________
Find the electric field strength 0.30 m from a point charge of +5.0 nC.[3]
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500 N/C. 8.99 × 10⁹ × 5.0 × 10⁻⁹ ÷ 0.30².
The distance between two charges is tripled. State what happens to the force between them.[2]
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It falls to one ninth.
Two equal positive charges are 0.20 m apart. State the field strength at the point midway between them, and explain your answer.[2]
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Zero. The fields due to the two charges are equal in size and opposite in direction there, so they cancel.
State one similarity and one difference between electric fields and gravitational fields.[2]
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Similarity: both follow an inverse square law for a point source (or both are force fields that act at a distance). Difference: gravitational forces are always attractive, but electric forces can attract or repel.
Answers: Coulomb's law and point charges
- 1. 500 N/C. 8.99 × 10⁹ × 5.0 × 10⁻⁹ ÷ 0.30².
- 2. It falls to one ninth.
- 3. Zero. The fields due to the two charges are equal in size and opposite in direction there, so they cancel.
- 4. Similarity: both follow an inverse square law for a point source (or both are force fields that act at a distance). Difference: gravitational forces are always attractive, but electric forces can attract or repel.



