Geometric progressions Cambridge IGCSE Additional Mathematics revision
Not started
Learn it
In plain words
3, 6, 12, 24: multiply by 2 each time. A sequence where each term is the last one times a fixed number is a geometric progression. If that number is a fraction, the terms shrink, and something remarkable happens: the sum of all of them, for ever, is a finite number.
6 things to know
- In a geometric progression, each term is the one before multiplied by the common ratio, r. The first term is a.
- The nth term is arⁿ⁻¹.
- The sum of the first n terms is Sₙ = a(1 − rⁿ) ÷ (1 − r), for r ≠ 1.
- If r is between −1 and 1, the progression converges, and it has a sum to infinity: S∞ = a ÷ (1 − r).
- If r is 1 or more, or −1 or less, the terms do not shrink towards zero, and there is no sum to infinity.
- To find r, divide any term by the one before it.
Worked example
For the progression 3, 6, 12, …, find the 8th term and the sum of the first 8 terms.
- a = 3 and r = 2.
- 8th term = 3 × 2⁷ = 384.
- S₈ = 3(1 − 2⁸) ÷ (1 − 2) = 3 × 255 = 765.
Worked example
Find the sum to infinity of 16 + 8 + 4 + ….
- a = 16 and r = 1/2. Since r is between −1 and 1, the sum to infinity exists.
- S∞ = 16 ÷ (1 − 1/2) = 32.
Tips and tricks
- The nth term has the power n − 1, not n. The 8th term uses r⁷.
- Before using the sum to infinity, state that |r| < 1. A question may ask you to explain why a sum to infinity does or does not exist.
It lands in your notebook with its questions as flashcards.
Geometric progressions: 5 questions and answers
These are the quiz’s questions. Do the quiz first, then come back here for the ones that got you.
What is the common ratio of 4, 12, 36, 108, …?
Each term is 3 times the one before.
What is the 5th term of the progression with a = 2 and r = 3?
2 × 3⁴.
When does a geometric progression have a sum to infinity?
The terms must shrink towards zero.
What is the sum to infinity of 10 + 5 + 2.5 + …?
10 ÷ (1 − 1/2).
Which sequence is a geometric progression?
It has a constant ratio of 2.
Quiz
5 questions
Tap an answer and you’ll see straight away whether it’s right, and why.
Worksheet
3 questions, 7 marks. Write your answers on paper, then check them.
Geometric progressions
Cambridge IGCSE Additional Mathematics 0606 · 7 marks · papermunch.org
Name ______________________________ Date ______________
A geometric progression has first term 5 and common ratio 3. Find the 6th term and the sum of the first 6 terms.[3]
Show answerHide answer
The 6th term is 1215. The sum is 1820. 5 × 3⁵, and 5(3⁶ − 1) ÷ 2.
Find the sum to infinity of 27 + 9 + 3 + ….[2]
Show answerHide answer
40.5. 27 ÷ (1 − 1/3).
Explain why the progression 2 + 6 + 18 + … has no sum to infinity.[2]
Show answerHide answer
Its common ratio is 3, which is not between −1 and 1, so the terms get larger and the sum does not converge.
Answers: Geometric progressions
- 1. The 6th term is 1215. The sum is 1820. 5 × 3⁵, and 5(3⁶ − 1) ÷ 2.
- 2. 40.5. 27 ÷ (1 − 1/3).
- 3. Its common ratio is 3, which is not between −1 and 1, so the terms get larger and the sum does not converge.



