Discharging a capacitor Edexcel International A Level Physics revision
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In plain words
Let a charged capacitor empty through a resistor and it starts fast and gets slower and slower, like a bath draining as the water level drops. In each equal stretch of time it loses the same fraction of what is left. That pattern is called exponential decay.
4 things to know
- When a capacitor discharges through a resistor, its charge, its p.d. and the current all fall exponentially: Q = Q₀e^(−t/RC), and the same for V and I.
- The time constant is RC, in seconds. It is the time for the charge (or the p.d., or the current) to fall to 1/e of its starting value, which is about 37%.
- On a graph against time, each quantity falls steeply at first and then more and more gently, never quite reaching zero.
- Taking logs gives ln Q = ln Q₀ − t ÷ RC. So a graph of ln Q (or ln V, or ln I) against t is a straight line with gradient −1 ÷ RC.
Worked example
A 100 µF capacitor charged to 12 V discharges through a 50 kΩ resistor. Find the time constant, and the p.d. after 10 s.
- Time constant = RC = 50 × 10³ × 100 × 10⁻⁶ = 5.0 s.
- V = V₀e^(−t/RC) = 12 × e^(−10 ÷ 5.0) = 12 × e⁻².
- = 12 × 0.135 = 1.6 V.
Tips and tricks
- With R in ohms and C in farads, RC comes out in seconds.
- After one time constant 37% is left; after two, about 14%; after five, less than 1%.
It lands in your notebook with its questions as flashcards.
Discharging a capacitor: 5 questions and answers
These are the quiz’s questions. Do the quiz first, then come back here for the ones that got you.
What is the time constant of a capacitor discharging through a resistor?
A bigger resistance or a bigger capacitance gives a slower discharge.
What fraction of its charge is left on a capacitor after one time constant?
1 ÷ e is 0.37.
The resistance a capacitor discharges through is doubled. What happens to the time it takes to discharge?
The time constant RC doubles.
What does a graph of ln V against t look like for a discharging capacitor?
Its gradient is −1 ÷ RC.
A capacitor charged to 10 V begins to discharge through a 2 kΩ resistor. What is the current at the start?
I = V ÷ R at that instant.
Quiz
5 questions
Tap an answer and you’ll see straight away whether it’s right, and why.
Worksheet
4 questions, 10 marks. Write your answers on paper, then check them.
Discharging a capacitor
Edexcel International A Level Physics WPH · 10 marks · papermunch.org
Name ______________________________ Date ______________
Find the time constant of a 470 µF capacitor discharging through a 10 kΩ resistor.[2]
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4.7 s.
A capacitor discharges with a time constant of 5.0 s. Find the time it takes for its charge to halve.[3]
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3.5 s. e^(−t/RC) = 0.50, so t = RC × ln 2 = 5.0 × 0.693.
A capacitor discharges through a 20 kΩ resistor. A graph of ln V against t has a gradient of −0.25 s⁻¹. Find the capacitance.[3]
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2.0 × 10⁻⁴ F (200 µF). RC = 1 ÷ 0.25 = 4.0 s, and C = 4.0 ÷ 20 × 10³.
A capacitor charged to 6.0 V starts to discharge through a 3.0 kΩ resistor. Find the current at the start, and state what happens to it afterwards.[2]
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2.0 mA. It then falls exponentially towards zero.
Answers: Discharging a capacitor
- 1. 4.7 s.
- 2. 3.5 s. e^(−t/RC) = 0.50, so t = RC × ln 2 = 5.0 × 0.693.
- 3. 2.0 × 10⁻⁴ F (200 µF). RC = 1 ÷ 0.25 = 4.0 s, and C = 4.0 ÷ 20 × 10³.
- 4. 2.0 mA. It then falls exponentially towards zero.



