Impulse and types of collision Edexcel International A Level Physics revision
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In plain words
A force changes momentum, and how much depends on how long it acts: a small force for a long time can do the same job as a big force for a short time. That's why airbags work. And although momentum is conserved in every collision, kinetic energy usually isn't, which gives a way of sorting collisions into types.
4 things to know
- Force = rate of change of momentum: F = Δp ÷ Δt. Impulse = FΔt = Δp, which is the area under a force–time graph.
- In an elastic collision the total kinetic energy is conserved, and the relative speed of approach equals the relative speed of separation. In an inelastic collision some kinetic energy is transferred to other forms, but momentum is still conserved.
- In two dimensions, momentum is conserved separately in each of two perpendicular directions.
- Kinetic energy can be written in terms of momentum: E = p² ÷ 2m.
Worked example
A 0.15 kg ball hits a wall at 20 m/s and rebounds at 15 m/s. The contact lasts 0.050 s. Find the average force on the ball.
- Take away from the wall as positive: the velocity is −20 m/s before and +15 m/s after.
- Change in momentum = 0.15 × (15 − (−20)) = 5.25 kg m/s.
- Force = 5.25 ÷ 0.050 = 105 N, away from the wall.
Tips and tricks
- A ball that bounces back has changed its momentum by more than one that just stops. Watch the signs.
- To test whether a collision is elastic, work out the total kinetic energy before and after and compare them.
It lands in your notebook with its questions as flashcards.
Impulse and types of collision: 6 questions and answers
These are the quiz’s questions. Do the quiz first, then come back here for the ones that got you.
What is the impulse of a 20 N force acting for 0.50 s?
Impulse = force × time.
What does the area under a force–time graph represent?
That is the impulse.
A 1000 kg car moving at 20 m/s is brought to rest in 4.0 s. What is the average force on it?
20 000 kg m/s ÷ 4.0 s.
What is true of an elastic collision?
Both momentum and kinetic energy are the same before and after.
How is momentum conserved in a collision in two dimensions?
Momentum is a vector, so each component is conserved.
Two objects approach each other head-on with a relative speed of 6 m/s and collide elastically. What is their relative speed of separation?Stretch
In an elastic collision the speed of approach equals the speed of separation.
Quiz
6 questions
Tap an answer and you’ll see straight away whether it’s right, and why.
Worksheet
4 questions, 10 marks. Write your answers on paper, then check them.
Impulse and types of collision
Edexcel International A Level Physics WPH · 10 marks · papermunch.org
Name ______________________________ Date ______________
A 2.0 kg trolley moving at 3.0 m/s hits a stationary 1.0 kg trolley, and they move off together at 2.0 m/s. Show that the collision is inelastic.[3]
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Kinetic energy before = ½ × 2.0 × 3.0² = 9.0 J. After = ½ × 3.0 × 2.0² = 6.0 J. Kinetic energy is not conserved, so the collision is inelastic.
Explain why a car's crumple zone reduces the force on the passengers in a crash.[2]
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It increases the time taken to stop. The change in momentum is the same, so the rate of change of momentum, and therefore the force, is smaller.
A 0.20 kg ball moving at 5.0 m/s in the x-direction is deflected so that it moves at 5.0 m/s in the y-direction. Find the magnitude of its change in momentum.[3]
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1.4 kg m/s. The change has components of −1.0 and +1.0 kg m/s: √(1.0² + 1.0²).
Find the kinetic energy of a 2.0 kg object that has a momentum of 6.0 kg m/s.[2]
Show answerHide answer
9.0 J. 6.0² ÷ (2 × 2.0).
Answers: Impulse and types of collision
- 1. Kinetic energy before = ½ × 2.0 × 3.0² = 9.0 J. After = ½ × 3.0 × 2.0² = 6.0 J. Kinetic energy is not conserved, so the collision is inelastic.
- 2. It increases the time taken to stop. The change in momentum is the same, so the rate of change of momentum, and therefore the force, is smaller.
- 3. 1.4 kg m/s. The change has components of −1.0 and +1.0 kg m/s: √(1.0² + 1.0²).
- 4. 9.0 J. 6.0² ÷ (2 × 2.0).



