Stretching and Hooke's law Edexcel International GCSE Science (Double Award) revision
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In plain words
Pull on a spring and it gets longer. For a while the stretch is fair: double the pull, double the extension. That's Hooke's law. Pull too hard and you pass the limit of proportionality: the spring stretches more than it should, and may not go back.
Three things to know
- For a spring, extension is proportional to load up to the limit of proportionality (Hooke's law): F = kx.
- The spring constant k is the force per unit extension, in N/m or N/cm. A stiffer spring has a bigger k.
- Extension is the stretched length minus the original length, not the total length.
Worked example
A spring stretches 4 cm with a 2 N load. What is its spring constant?
- k = force ÷ extension.
- = 2 ÷ 4 = 0.5 N/cm.
Tips and tricks
- Extension is the extra length, not the total length. Subtract the original length first.
- On a graph, Hooke's law holds only while the line is straight and passes through the origin.
It lands in your notebook with its questions as flashcards.
Stretching and Hooke's law: 6 questions and answers
These are the quiz’s questions. Do the quiz first, then come back here for the ones that got you.
A spring stretches 2 cm with a 1 N load. If it obeys Hooke's law, how far does it stretch with 3 N?
Three times the load gives three times the extension.
What does a larger spring constant tell you?
More force is needed for each metre of extension.
A load–extension graph for a spring is a straight line through the origin. What does this show?
A straight line through the origin means one doubles when the other does.
A spring of original length 10 cm is 16 cm long when loaded. What is its extension?
Extension = new length − original length.
A force of 12 N extends a spring by 0.30 m. What is its spring constant?
k = F ÷ x = 12 ÷ 0.30.
What happens to a spring stretched beyond its elastic limit?
It is permanently deformed.
Quiz
6 questions
Tap an answer and you’ll see straight away whether it’s right, and why.
Worksheet
4 questions, 9 marks. Write your answers on paper, then check them.
Stretching and Hooke's law
Edexcel International GCSE Science (Double Award) 4SD0 · 9 marks · papermunch.org
Name ______________________________ Date ______________
A spring is 12.0 cm long. With a 4.0 N load it is 17.0 cm long. Calculate the extension.[2]
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5.0 cm. 17.0 − 12.0.
A force of 6.0 N stretches a spring by 0.15 m. Calculate the spring constant.[2]
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40 N/m. k = F ÷ x = 6.0 ÷ 0.15.
A spring has a spring constant of 25 N/m. Calculate the force needed to extend it by 8.0 cm.[3]
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2.0 N. 8.0 cm = 0.080 m; F = kx = 25 × 0.080.
State what is meant by the limit of proportionality.[2]
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The point beyond which extension is no longer proportional to load (the graph stops being a straight line).
Answers: Stretching and Hooke's law
- 1. 5.0 cm. 17.0 − 12.0.
- 2. 40 N/m. k = F ÷ x = 6.0 ÷ 0.15.
- 3. 2.0 N. 8.0 cm = 0.080 m; F = kx = 25 × 0.080.
- 4. The point beyond which extension is no longer proportional to load (the graph stops being a straight line).



