Factorising and solving cubic equations Cambridge IGCSE Additional Mathematics revision
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In plain words
A cubic can have up to three solutions. Finding them takes two steps: hunt for one root by trying small numbers, then divide it out. What is left is a quadratic, and you already know how to deal with those.
5 things to know
- Step 1: try small whole numbers, such as 1, −1, 2 and −2, in the cubic until one gives 0. That number is a root, and it gives a linear factor.
- Step 2: divide the cubic by that linear factor to get a quadratic. This can be done by long division or by comparing coefficients.
- Step 3: factorise the quadratic, or solve it with the formula.
- The roots to try are factors of the constant term.
- A cubic equation has at most three real roots.
Worked example
Solve x³ − 6x² + 11x − 6 = 0.
- Try x = 1: 1 − 6 + 11 − 6 = 0. So (x − 1) is a factor.
- Divide: x³ − 6x² + 11x − 6 = (x − 1)(x² − 5x + 6).
- Factorise the quadratic: (x − 1)(x − 2)(x − 3) = 0.
- x = 1, x = 2 or x = 3.
Worked example
Factorise 2x³ + 3x² − 11x − 6 completely.
- Try x = 2: 16 + 12 − 22 − 6 = 0. So (x − 2) is a factor.
- The quadratic factor starts with 2x² and ends with +3, since −2 × 3 = −6: (x − 2)(2x² + kx + 3). Matching the x² terms, k − 4 = 3, so k = 7.
- 2x² + 7x + 3 = (2x + 1)(x + 3). The answer is (x − 2)(2x + 1)(x + 3).
Tips and tricks
- Show the substitution that finds the first factor. An answer with no method may not earn full marks on the non-calculator paper.
- Check the constant: the last terms of the three brackets must multiply to give the constant of the cubic.
It lands in your notebook with its questions as flashcards.
Factorising and solving cubic equations: 5 questions and answers
These are the quiz’s questions. Do the quiz first, then come back here for the ones that got you.
What are the roots of (x − 1)(x + 2)(x − 4) = 0?
Each bracket is set equal to 0.
What is the first step in factorising a cubic?
That value gives a linear factor.
What are the solutions of x³ − x = 0?
x(x − 1)(x + 1) = 0.
x³ − 6x² + 11x − 6 = (x − 1) × a quadratic. What is the quadratic?
Multiply back to check: the constant is −1 × 6 = −6.
What is the greatest number of real roots a cubic equation can have?
One for each linear factor.
Quiz
5 questions
Tap an answer and you’ll see straight away whether it’s right, and why.
Worksheet
2 questions, 7 marks. Write your answers on paper, then check them.
Factorising and solving cubic equations
Cambridge IGCSE Additional Mathematics 0606 · 7 marks · papermunch.org
Name ______________________________ Date ______________
Solve x³ + 2x² − 5x − 6 = 0.[4]
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x = 2, x = −1 or x = −3. p(2) = 0, and x³ + 2x² − 5x − 6 = (x − 2)(x² + 4x + 3) = (x − 2)(x + 1)(x + 3).
Factorise x³ − 7x + 6 completely.[3]
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(x − 1)(x − 2)(x + 3). p(1) = 0, and the quadratic factor is x² + x − 6.
Answers: Factorising and solving cubic equations
- 1. x = 2, x = −1 or x = −3. p(2) = 0, and x³ + 2x² − 5x − 6 = (x − 2)(x² + 4x + 3) = (x − 2)(x + 1)(x + 3).
- 2. (x − 1)(x − 2)(x + 3). p(1) = 0, and the quadratic factor is x² + x − 6.



