The remainder and factor theorems Cambridge IGCSE Additional Mathematics revision

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In plain words

Dividing a polynomial by something like (x − 2) is slow. The remainder theorem gives the remainder in one line, by substituting a number. And when that remainder is zero, you have found a factor.

4 things to know

  1. The remainder theorem: when a polynomial p(x) is divided by (x − a), the remainder is p(a).
  2. For a divisor (ax − b), the remainder is p(b/a): use the value of x that makes the divisor zero.
  3. The factor theorem: (x − a) is a factor of p(x) exactly when p(a) = 0.
  4. These are used to find unknown coefficients: substitute, and set the result equal to the given remainder, or to 0 for a factor.

Worked example

p(x) = x³ + 2x² − 5x − 6. Find the remainder when p(x) is divided by (x − 1), and show that (x − 2) is a factor.

  1. Remainder on division by (x − 1): p(1) = 1 + 2 − 5 − 6 = −8.
  2. p(2) = 8 + 8 − 10 − 6 = 0.
  3. Since p(2) = 0, (x − 2) is a factor.

Worked example

When 2x³ + ax² − 3x + 4 is divided by (x − 2), the remainder is 10. Find a.

  1. p(2) = 16 + 4a − 6 + 4 = 14 + 4a.
  2. 14 + 4a = 10, so 4a = −4 and a = −1.

Tips and tricks

  • The sign flips: for (x − 2) substitute 2, and for (x + 3) substitute −3.
  • To "show that" something is a factor, write the substitution out in full and finish with "= 0, so it is a factor".
5 questions, about 2 minutes.

It lands in your notebook with its questions as flashcards.

The remainder and factor theorems: 5 questions and answers

These are the quiz’s questions. Do the quiz first, then come back here for the ones that got you.

  1. What is the remainder when x² + 3x + 5 is divided by (x − 1)?
    • 5
    • 7
    • 9 (the answer)
    • 3

    Substitute x = 1: 1 + 3 + 5.

  2. p(a) = 0. What does this tell you?
    • (x + a) is a factor of p(x)
    • (x − a) is a factor of p(x) (the answer)
    • p(x) has no factors
    • the remainder is a

    That is the factor theorem.

  3. Which value should be substituted to test whether (x + 3) is a factor?
    • 3
    • −3 (the answer)
    • 0
    • 1/3

    The value that makes x + 3 equal to 0.

  4. What is the remainder when 2x³ − x + 1 is divided by (x + 1)?
    • 0 (the answer)
    • 2
    • −2
    • 4

    p(−1) = −2 + 1 + 1 = 0, so (x + 1) is a factor.

  5. Which value should be substituted to find the remainder on division by (2x − 1)?
    • 1
    • 2
    • 1/2 (the answer)
    • −1/2

    2x − 1 = 0 when x = 1/2.

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