The remainder and factor theorems Cambridge IGCSE Additional Mathematics revision
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In plain words
Dividing a polynomial by something like (x − 2) is slow. The remainder theorem gives the remainder in one line, by substituting a number. And when that remainder is zero, you have found a factor.
4 things to know
- The remainder theorem: when a polynomial p(x) is divided by (x − a), the remainder is p(a).
- For a divisor (ax − b), the remainder is p(b/a): use the value of x that makes the divisor zero.
- The factor theorem: (x − a) is a factor of p(x) exactly when p(a) = 0.
- These are used to find unknown coefficients: substitute, and set the result equal to the given remainder, or to 0 for a factor.
Worked example
p(x) = x³ + 2x² − 5x − 6. Find the remainder when p(x) is divided by (x − 1), and show that (x − 2) is a factor.
- Remainder on division by (x − 1): p(1) = 1 + 2 − 5 − 6 = −8.
- p(2) = 8 + 8 − 10 − 6 = 0.
- Since p(2) = 0, (x − 2) is a factor.
Worked example
When 2x³ + ax² − 3x + 4 is divided by (x − 2), the remainder is 10. Find a.
- p(2) = 16 + 4a − 6 + 4 = 14 + 4a.
- 14 + 4a = 10, so 4a = −4 and a = −1.
Tips and tricks
- The sign flips: for (x − 2) substitute 2, and for (x + 3) substitute −3.
- To "show that" something is a factor, write the substitution out in full and finish with "= 0, so it is a factor".
It lands in your notebook with its questions as flashcards.
The remainder and factor theorems: 5 questions and answers
These are the quiz’s questions. Do the quiz first, then come back here for the ones that got you.
What is the remainder when x² + 3x + 5 is divided by (x − 1)?
Substitute x = 1: 1 + 3 + 5.
p(a) = 0. What does this tell you?
That is the factor theorem.
Which value should be substituted to test whether (x + 3) is a factor?
The value that makes x + 3 equal to 0.
What is the remainder when 2x³ − x + 1 is divided by (x + 1)?
p(−1) = −2 + 1 + 1 = 0, so (x + 1) is a factor.
Which value should be substituted to find the remainder on division by (2x − 1)?
2x − 1 = 0 when x = 1/2.
Quiz
5 questions
Tap an answer and you’ll see straight away whether it’s right, and why.
Worksheet
3 questions, 7 marks. Write your answers on paper, then check them.
The remainder and factor theorems
Cambridge IGCSE Additional Mathematics 0606 · 7 marks · papermunch.org
Name ______________________________ Date ______________
Find the remainder when x³ − 4x² + x + 7 is divided by (x − 3).[2]
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1. 27 − 36 + 3 + 7.
Show that (x + 1) is a factor of x³ + 4x² + x − 2.[2]
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p(−1) = −1 + 4 − 1 − 2 = 0, so (x + 1) is a factor.
(x − 2) is a factor of x³ + kx² − 4x + 8. Find the value of k.[3]
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k = −2. p(2) = 8 + 4k − 8 + 8 = 0, so 4k = −8.
Answers: The remainder and factor theorems
- 1. 1. 27 − 36 + 3 + 7.
- 2. p(−1) = −1 + 4 − 1 − 2 = 0, so (x + 1) is a factor.
- 3. k = −2. p(2) = 8 + 4k − 8 + 8 = 0, so 4k = −8.



