Simultaneous equations: one linear, one not Cambridge IGCSE Additional Mathematics revision
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In plain words
A straight line and a curve usually meet at two points. Finding them means solving both equations at once, and there is only one sensible way: use the line to get rid of a letter.
5 things to know
- Rearrange the linear equation to give x or y.
- Substitute into the other equation. This leaves a quadratic in one letter.
- Solve the quadratic. There are usually two values.
- Put each value into the linear equation to find the other letter. Give the answers as pairs.
- If the quadratic has equal roots, the line is a tangent to the curve.
Worked example
Solve y = x + 1 and x² + y² = 25.
- Substitute for y: x² + (x + 1)² = 25.
- Expand: 2x² + 2x + 1 = 25, so x² + x − 12 = 0.
- Factorise: (x − 3)(x + 4) = 0, so x = 3 or x = −4.
- From y = x + 1: y = 4 or y = −3. The solutions are x = 3, y = 4 and x = −4, y = −3.
Tips and tricks
- Substitute back into the linear equation, not the curve. It is easier, and it cannot give extra false answers.
- Pair the answers up. Writing "x = 3, −4 and y = 4, −3" without saying which goes with which can lose a mark.
It lands in your notebook with its questions as flashcards.
Simultaneous equations: one linear, one not: 5 questions and answers
These are the quiz’s questions. Do the quiz first, then come back here for the ones that got you.
What is the first step in solving a linear and a quadratic equation together?
One letter is eliminated.
How many pairs of solutions are there usually?
A line usually cuts a curve of this kind twice.
What are the solutions of y = x and x² + y² = 8?
2x² = 8 gives x = 2 or −2, and y = x.
Where does the line y = x + 2 meet the curve y = x²?
x² − x − 2 = 0 gives x = 2 or −1.
The quadratic formed has two equal roots. What does that mean?
They meet at one point only.
Quiz
5 questions
Tap an answer and you’ll see straight away whether it’s right, and why.
Worksheet
2 questions, 8 marks. Write your answers on paper, then check them.
Simultaneous equations: one linear, one not
Cambridge IGCSE Additional Mathematics 0606 · 8 marks · papermunch.org
Name ______________________________ Date ______________
Solve y = 2x − 1 and y = x² − 4.[4]
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x = 3, y = 5 and x = −1, y = −3. x² − 2x − 3 = 0.
Solve x + y = 5 and xy = 6.[4]
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x = 2, y = 3 and x = 3, y = 2. x(5 − x) = 6 gives x² − 5x + 6 = 0.
Answers: Simultaneous equations: one linear, one not
- 1. x = 3, y = 5 and x = −1, y = −3. x² − 2x − 3 = 0.
- 2. x = 2, y = 3 and x = 3, y = 2. x(5 − x) = 6 gives x² − 5x + 6 = 0.



